通關要素包含正確的隊伍、技術、+值、耐性、精力和最重要的運氣。最後一擊!
Monday, May 11, 2015
絕無限迴廊 clear!
經過日復一日的嘗試和失敗(水時隊見本帖),最後終於以覺醒火印攻克這一關卡了 ...。
比古洛的 2 手指覺醒,4way 還有那龐大的血量和攻擊力,十分值得把 +值 投資落去。需然他是十分優秀的隊長,但在火印面前還是乖乖的當隊員吧。
把餘下的迴廊清掉後:
看到 clear 字樣十分滿足!
Saturday, May 9, 2015
Sony Z3C 終於可以吃糖,拍片!極限大和 challenge
終於升到 android 5.0,很興奮地立刻嘗試 google play noroot 但需要 5.0 的拍片 app。sony 有內置的錄影程式,但程式會嚴重影響手機效能,因此必須找一個能順暢錄影而解像度能壓低一點的 app。
此 challenge 通關後只有一石,沒有額外獎勵,真的不值得浪費體力打。
Friday, May 8, 2015
Thursday, May 7, 2015
Record an observation
Let $\Omega$ be a measure space, a $\sigma$-algebra of subsets of $\Omega$ is said to be finite if it is generated by finitely many subsets $X_1,\dots,X_n\subseteq \Omega$.
Observation. A random variable $X$ on $\Omega$ is simple if and only if it is measurable w.r.t. a finite $\sigma$-algebra.
Proof. Suppose that $X=\sum _{i=1}^nx_i I_{A_i}$, then the $\sigma$-algebra induced by $X$ is precisely $\sigma(A_1,\dots,A_n)$, which is finite. Conversely, suppose that $X$ is measurable on $\Sigma=\sigma(B_1,\dots,B_n)$, then every element in $\sigma(B_1,\dots,B_n)$ is a finite union of elements in some measurable partition $\mathcal C=\{C_1,\dots,C_M\}$. Moreover, since $X^{-1}(B)$ is $\Sigma$-measurable for every Borel set $B$, the disjoint collection $\{X^{-1}(\{a\})\}_{a\in \R}$ must have at most finitely many ($\leq 2^M$) elements, thus we are done.
Observation. A random variable $X$ on $\Omega$ is simple if and only if it is measurable w.r.t. a finite $\sigma$-algebra.
Proof. Suppose that $X=\sum _{i=1}^nx_i I_{A_i}$, then the $\sigma$-algebra induced by $X$ is precisely $\sigma(A_1,\dots,A_n)$, which is finite. Conversely, suppose that $X$ is measurable on $\Sigma=\sigma(B_1,\dots,B_n)$, then every element in $\sigma(B_1,\dots,B_n)$ is a finite union of elements in some measurable partition $\mathcal C=\{C_1,\dots,C_M\}$. Moreover, since $X^{-1}(B)$ is $\Sigma$-measurable for every Borel set $B$, the disjoint collection $\{X^{-1}(\{a\})\}_{a\in \R}$ must have at most finitely many ($\leq 2^M$) elements, thus we are done.
Monday, May 4, 2015
Record a command
defaults -currentHost write -g AppleFontSmoothing -int 2
(4 is apple default)
http://embdev.net/topic/284710#3027030
(4 is apple default)
http://embdev.net/topic/284710#3027030
Saturday, May 2, 2015
出糧,再給 apple 課金
只限一次 challenge 地下城
照舊紀錄一下通關隊伍:
Lv 8. 試了一石,我打了很久才發現尾 2 關的維納斯是水屬減半,虧我還拿水印隊,某些光隊去嘗試。最後靠劉備的 UUU 通關。圖為給撒旦最後一擊時的盤面,沒有辦法發動 15 倍攻擊力。
Lv 9. 因覺醒無效,初時想想怎樣通關時感動非常苦惱,但仔細想想我平時的水印隊是 25 倍隊純色隊呀!就算沒有覺醒技能本來已經很強。因沒有手指(這隊有 3 隻),不能像以前那樣瞎轉 5 心 5C。
值得一提的是看到嵐龍,再看看 data,才發現這貨意外的軟 ...。
Lv 10. 很難 0石 的一關,打了一小時,最後發現上面的隊型可行。最麻煩的是第 3 關出現的 4 隻 pi,hp24,單隻攻擊 7707,沒有 3 萬血根本不能用生命硬接。取而代之我用孫權在這層威嚇,慢慢調校 "火力" 儲技。第 4 關的木印對這隊沒有壓力,因她最大的攻擊力才 25000 多,可硬接。
最後王關的火印非常考運氣。他強制減我方寵物 2CD,還會把第一、二、三直行換成火,卡心珠機率極高。幸好捱過兩回合,開技順利把他秒掉!
事後再想想,如要避免在王關看面(減 2 CD),我可以在尾 2(木印)那關把孫權存起,威嚇 → 秒 → 木印根性 → 水時 + 杜拉 → 口水幹掉木印 → 在王關爆發 → 收 pi。
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