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Thursday, April 1, 2010

Problem on function + simple inequality from AL discussion.

Recently solved a problem that is given from my classmate. (the solution is confirmed to be right by Kin Li, at least at the moment I post the question here) You can try the following one.

Problem 1. Let f:[0,1][0,1],g:[0,1][0,1] be continuous and satisfy fg(x)=gf(x). Prove that there is a w[0,1] such that f(w)=g(w).

I think it is not that easy. :)

Problem 2. Suppose a,b,c>0 and ab+bc+ca=13, show that aa2bc+1+bb2ca+1+cc2ab+11a+b+c.

Once again, AL knowledge is enough.

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